17x^2+60x=49

Solution for 17x^2+60x=49 equation:

17x^2+60x=49

We move all terms to the left:

17x^2+60x-(49)=0

a = 17; b = 60; c = -49;
Δ = b2-4ac
Δ = 602-4·17·(-49)
Δ = 6932
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6932}=\sqrt{4*1733}=\sqrt{4}*\sqrt{1733}=2\sqrt{1733}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{1733}}{2*17}=\frac{-60-2\sqrt{1733}}{34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{1733}}{2*17}=\frac{-60+2\sqrt{1733}}{34}
$